These are my live-TeXed notes for the course Math 270x: Topics in Automorphic Forms taught by Jack Thorne at Harvard, Fall 2013.
Any mistakes are the fault of the notetaker. Let me know if you notice any mistakes or have any comments!
Recommended references for this course:
- Diamond, Shurman, Introduction to modular forms;
- Borel, Casselman, Automorphic forms, representations and L-function (Corvallis);
- Bushnell, Henniart, Local Landlands conjecture for GL(2);
- Bernstein, Gelbart, Introduction to the Langlands program.
09/10/2013
Modular forms and number fields
The absolute Galois group contains huge arithmetic information. One can ask algebraic number theoretic questions like: for which prime , is a quotient of (i.e., there exists a number field with such a Galois group)? Or how to describe Galois extensions of with prescribed local ramification behavior at a prime ? Miraculously that these kinds of questions can be answered using modular/automorphic forms and furthermore automorphic forms can be understood by the Langlands dual group .
(Eisenstein series)
For
, we define the
weight Eisenstein series It is easy to show that this series converges absolutely and converges uniformly in any compact subset of
. Notice that
acts on
on the right. The stabilizer of
is
. Thus
The weak modularity of
follows from the modular cocycle property of
.
is uniformly convergent in
and thus
So
is bounded as
. We have verified that
is a modular form of weight on
. A standard fact is that
has a nice
-expansion:
where
is the
-th Bernoulli number (a rational number).
The
Ramanujan modular function is defined to be
It is a
cusp form of weight 12 on
.
is the unique (up to scalar) cusp form on
of minuscule weight (i.e., there is no cusp forms of weight
on
). Moreover, all the coefficients of
-expansion of
are indeed integers.
Hecke operators The quotient has representatives , where and . One can then explicitly compute In other words, It follows directly that for .
Peterson inner product Fix an integer . For two holomorphic functions on , we define . One computes that In particular, is -invariant when . For , converges and defines a Hermitian positive definite inner product, called the Peterson inner product.
An important fact is that is self-adjoint with respect to the Peterson inner product. Therefore we can simultaneously diagonalize these commuting Hecke operators to obtain a basis of such that every is a -eigenvector with real eigenvalue for any .
The upshot is that starting from a weight , we obtain real numbers (the -eigenvalues) and modular forms indexed by the prime numbers . We can associate to this basis Galois representations (or motives) and doing becomes useful for constructing extensions of with prescribed behavior.
Let
and
be the
-th isotypic part of
. Herbrand and Ribet proved that for
, it is true that
if and only if
. In particular, when
, by class field theory, there exists a unramified
-extension of
corresponding to
. How do we construct this extension? Ribet managed to do so using modular forms. For example:
divides
and the explicit formula gives a congruence between
and
modulo
; the desired extension of
is then constructed using the Galois representation attached to
.
09/12/2013
Automorphic representations on
It begins to reveal the remarkable nature of modular/automorphic forms when you add a little bit representation theory.
Let
be a number field and
be the ring of adeles of
. The group
is defined to be the restricted direct product
with respect to the open compact subgroups
. Notice as an abstract group
is simply the group of invertible matrices with entries in
. We now consider
and write
for short.
This complicated definition generalizes the classical notion of modular forms (the advantage is that it puts the representation theory in scope as we consider all levels ).
Suppose the open compact subgroup
satisfies
. Then
is a congruence subgroup of
and
To prove the theorem, we need the following
- Pick an arbitrary lift . We would like a matrix such that and . By multiplying on the left and right by , we may assume . Then and the matrix is desired.
- Using and , we know that there is a bijection between free -modules in of rank and free module of of rank given by , . Consequently, it gives a bijection . In particular the desired result follows.
- Let . Use part (b) to write , where , . Taking determinants, we know . The claim follows from changing by an element of if necessary.
¡õ
(Strong approximation for )
is dense in
.
Let
be any open compact subgroup. We will show that
. We may assume that
, where
. By (c) of the previous lemma, we can write
as
, where
and
. By (a) of the previous lemma, we can find
such that
. Then
.
¡õ
Let
be an open compact subgroup such that
. Then
- .
- It follows from the and the strong approximation of .
- It follows from the first part because acts transitively on .
¡õ
(Theorem 1)
The bijection is constructed as
and
, where
such that
, whose existence is assured by the previous corollary. (One needs to check the latter is well-defined and
thus defined is a modular form of level
).
¡õ
The most interesting thing is that the group acts on both of the spaces by (so if ).
An
automorphic representation of weight
is an irreducible representation
of
which is isomorphic to a subquotient of
. Similarly, a
cuspidal automorphic representation is a subquotient of
.
Representations of locally profinite groups
A representation of means more precisely the following.
A
representation of a locally profinite group
is a pair
, where
is a
-vector space and
is a homomorphism. A representation
is called
smooth if for any
, there exists an open compact subgroup
such that
. It is called
admissible if it is smooth and
is finite dimensional for any open compact subgroup
.
09/17/2013
Let
(here
stands for compactly supported and
stands for locally constant). This becomes a smooth representation of
under left and right translations:
For any
, one can write it as
where
is some compact open subgroup depending on
.
The group
and
are unimodular. In general, if
is any reductive group over
, then
is also unimodular.
Now fix an open compact subgroup
and normalize the Haar measure such that
. We define the
Hecke algebra to be the space of compactly supported, locally constant functions on
which are
-bi-invariant. In particular,
.
Let
. Then for any
,
if and only if
.
Since , it follows that is a subalgebra of with the unit .
- Let be a smooth representation of . Then for any , . Therefore is a -module.
- Let be an admissible irreducible representation of . Then either or is an irreducible -module. Moreover, if for such that , we have if and only if as -modules.
Now let us consider the case and . Every compact subgroup is contained in a -conjugate of and is a maximal compact subgroup.
We say an admissible irreducible representation
is
unramified if
.
Let
and
. Then
. In particular,
is commutative.
If
is an unramified representation of
. Then
is 1-dimensional, determined by the eigenvalues of
and
.
Back to automorphic representations on
When , we can write . Therefore the latter admits an action of , so is a -module, where and .
The operator
then induces an operator, still denoted by
, acting on
.
When
, this adelically defined operator agrees with the classical Hecke operators
acting on
. Indeed, decompose
and call these representatives
and
viewed as elements in
. Starting from
, we want to show that
. Notice
Define
as the
viewed as elements in
. Then
has entry 1 at the prime
and
at other primes
, hence is an elements of
. Thus
as desired when you expand the terms.
Similarly, induces a operator on . One can compute that .
Since is a semisimple representation of (Corollary 3), we can write where 's are the irreducibles. This implies that After reordering, we can assume (hence is 1-dimensional) if and only if . The isomorphism classes of , are then determined by the isomorphism class of as a -module, or even better, by the eigenvalues of and ().
09/19/2013
A smooth representation of a locally profinite group
is called
unitary if there exists a Hermitian positive definite inner product
that is
-invariant. When
is compact (e.g., finite), every irreducible representation is unitary.
If
is unitary and admissible representation of
, then it is
semisimple. Namely
where each
is irreducible and admissible.
By Zorn's lemma, it suffices to show that any
-invariant subspace of
has
-invariant complement, namely
. We will show that we can take
. By positive definiteness,
. It remains to show that
. Choose
an open compact subgroup. Recall that (Remark
6)
We then need to show that
. Because
is
finite dimensional, we have
. For any
a smooth irreducible of
,
is perpendicular to
(check this according
or
). We see that
, since
. It follows that
.
¡õ
If
, then
is a semisimple representation of
. So we can write
, where
runs over all cuspidal automorphic representations of
.
Want to show that
is a unitary representation. This is not quite true but there exists a character
such that
is unitary. The unitary structure is a generalization of the Peterson inner product which we will talk about next time. This is enough to show that
is semisimple by untwisting the direct sum decomposition of
.
¡õ
- is an irreducible admissible representation of , which only depends on and not on or 's.
- If is any irreducible admissible representation of , there exists 's such that . Moreover, the isomorphism class of the 's are uniquely determined.
The proof is purely algebraic, see Flath in Corvallis I. We do remark that the some holds if
is replaced by any restricted direct product
with respect to
such that for almost all
, the Hecke algebra
is commutative (e.g.,
for any reductive group
).
¡õ
We now can describe the summands of in classical terms.
- Let and a prime , then acts semisimply on and the , commute for a prime.
- If is an eigenform for all , , then the submodule of generated by is irreducible. Conversely, any irreducible submodules of is obtained in this way.
- Let be the irreducible submodules of such that (there are only finitely many by the admissibility of . As modules for , Then acts on the first factor trivially and acts on the second factor (which is 1-dimension) in the usual way. It follows that the action of is semisimple and , commute.
- We Need some nontrivial global information:
- (Multiplicity one) If are irreducible submodules such that , then . Namely, decomposes with multiplicity one.
- (Strong multiplicity one). If and are cuspidal automorphic representations of of weight such that for almost all (e.g., all unramified primes), , then .
Let be the submodule generated by . By the semisimplicity, we can write , where 's are irreducible. Notice that because these are unramified representations and their isomorphism class is determined by eigenvalue of on . Now we apply strong multiplicity to obtain and the multiplicity one implies that .
For the converse, we need some nontrivial local information:
Let
and define
If
is any irreducible admissible representations of
, then there exists
such that
. The smallest
is called the
conductor of
.
By this theorem, there exists such that (do it at one prime a time). If is a cuspidal automorphic representation, then we can chose . Then is a -eigenvector for all and generates .
¡õ
General automorphic representations on
Reference on this section:
- Gelbart, Automorphic forms on adeles groups
- Deligne, Formes modulaires et representations de GL(2)
Now we are going to also incorporate the representation theory at and enlarge the notion of automorphic forms and representations on . We write , , and . Then is a maximal compact subgroup of and write .
We define
Then
acts on the left on
(or
) by right translation and
acts on
by
This makes
(or
) into a representation of
and hence extends to a representation of
, the universal enveloping algebra of
. By linearity,
also acts on
(or
, where
.
The vector
spans
.
The vectors
and
are the eigenvectors for the adjoint action of
or
on
with non-zero eigenvalue. We have the commutant relations
Let
be the center of the universal enveloping algebra. One can show that
, where
and
is the
Casmir operator.
09/24/2013
We use the Iwasawa decomposition
, so any
has a unique decomposition
Using the fact that
, we see that
and the first part follows. For the second part, one compute the differential operator
and find out that
if and only if
.
¡õ
Let
, we associate to
a function
as above. Then it satisfies that (c.f., Definition
2)
- For any , is holomorphic.
- There exists open compact subgroup such that for any and , .
- For any and , .
- For any and , .
- For any , .
- .
- For any , there exists such that for any , where for , .
The above association
gives an isomorphism of
-modules
and the functions
satisfying the above 7 conditions. This restricts to an isomorphism between
and the
's which also satisfy
It is easy to check the isomorphism by construction. To match the cuspidality condition, it suffices to check on
of the form
,
. Using
and the Cauchy integral formula, we see that
where
.
¡õ
Let
be a
-module. We say that
is
admissible if for any
continuous irreducible, the isotypic subspace
is finite dimensional. We say
is
irreducible if it is algebraically irreducible, i.e. there is no proper
-submodule.
A
-module is a
-vector space
endowed with the structure of
-module and a commuting smooth action of
. We say
is
admissible if for any open compact subgroup
and for all continuous irreducible representations
, the isotypic subspace
is finite dimensional. Similarly, we say
is
irreducible is it is algebraically irreducible.
Suppose
is an irreducible admissible
-module, then there exists
as an irreducible admissible
-module and for all
, an irreducible admissible
-module, unramified for almost all
, such that
See Flath in Corvallis I.
¡õ
- The spaces and are naturally -modules.
- For any , generates an admissible -module.
- is semisimple (but is not).
This is theorem that requires real work. For part b): one needs reduction theory for
and also finiteness results of solutions to certain differential equations (highly nontrivial). For part c), one needs a generalization of Peterson inner product and the "unitary implies semisimple" result.
¡õ
An
automorphic representation of is an irreducible
-module which is isomorphic to a subquotient of
. It is
cuspidal if it is isomorphic to a subquotient of
.
- Let . We define a -module as follows. As a vector space As a -module, As a -module, and is defined to be the differentiate action of . Then is an irreducible admissible -module.
- If satisfies and , then generates a -submodule of which is isomorphic to .
09/26/2013
Reductive groups over algebraically closed fields
Convention. We will assume that is a field of characteristic 0. By a variety over we mean a reduced scheme of finite type over (not necessarily connected or irreducible). Any affine scheme is separated so we will not assume separatedness.
An
algebraic group is a variety endowed with morphisms
,
and a point
making
a group object in the category of varieties. A
representation of
is a pair
where
is a finite dimensional
-vector space and
is a homomorphism of algebraic groups. We say
is a
linear algebraic group if it admits a faithful representation.
A linear algebraic group
is
reductive if it is geometrically connected and every representation of
is
semisimple.
is a reductive group. If
is a number field and
is a reductive group, we will discuss a good theory of automorphic forms on
, generalizing the classical case
and
.
Reductive groups are nice from the perspective of representation theory. Even better, one can classify all reductive groups over an algebraically closed field using certain combinatoric data and classify them over general fields via descent.
Convention. In this section we assume that is algebraically closed.
A
torus is a linear algebraic group such that there exists an isomorphism
for some
. We define the
character group and the
cocharacter group of
,
These are free abelian groups of rank
.
- The natural pairing is a perfect paring.
- The assignment is an equivalence of categories between the category of -tori and the category of finitely generated free abelian groups.
- Every irreducible representation of is 1-dimensional and every representation of is semisimple (so is reductive).
Any representation of
is of the form
, where
.
The
derived group of a linear algebraic group
is defined to be
, where
runs over all closed normal subgroup such that
is abelian. The
derived central series is
. We say
is
solvable if this series terminates at the trivial group.
We recall the Jordan decomposition: If is a finite dimensional -vector space and , then there exists unique commuting elements such that ,where is diagonalizable and is unipotent. From this one can deduce the following theorem.
Let
be a linear algebraic group and
. Then there unique exists commuting elements
such that
and for
any representation
of
,
is semisimple and
is unipotent.
A linear algebraic group
is
unipotent of every
is unipotent.
The following proposition provides a intuitive way to think about the various notion of linear algebraic groups.
- Every connected solvable group admits a faithful representation with image in the subgroup of upper triangular matrices.
- Every unipotent group (in characteristic 0 it is automatically connected) admits a faithful representation with image in the subgroup of the unipotent upper triangular matrices.
- Every connected solvable group contains a unique normal unipotent group such that is a torus (we haven't defined quotients, one way to think about it is that there exists a torus such that is exact in -points). We call the unipotent part of .
The
radical of a linear algebraic group
is defined to be the maximal connected normal solvable subgroup. The
unipotent radical is defined to be the unipotent part of
.
Let
be a connected linear algebraic group. The
is reductive if and only if
is trivial.
Now we fix a reductive group .
We say a torus
(
means a closed subgroup) is
maximal if it is not contained in any strictly larger torus.
Fix a maximal torus . Then has a natural action on : given by differentiating the conjugation. Restricting to we obtain a natural representation of . This gives the Cartan decomposition where is the -eigenspace of for .
. Each
is either 0 or 1-dimensional.
The elements
such that
and
are called the
roots of
. We write
for the set of roots.
If
is a root, we define
and
(a reductive subgroup of
), then
is a maximal torus again.
The Weyl group
contains a unique nontrivial element
(so
has order 2) and there exits a unique element
such that
for all
. Namely,
acts on
by reflection and this reflection can be chosen using an
integral element
.
The element
is called the
coroot of the root
. We write
for the set of coroots. We have a canonical bijection between
and
given by
.
The tuple becomes a root datum in the following sense.
10/01/2013
Let
be a reductive group. A
Borel subgroup is a maximal connected solvable subgroup (not normal in general). A
parabolic subgroup is a subgroup such that
is projective as an algebraic variety.
Let
be a reductive group.
- contains a unique conjugacy class of Borel subgroups.
- A subgroup is parabolic if and only if it contains a Borel subgroup. In particular, Borel subgroups are parabolic.
. Fix a partition
into positive (= nonnegative) integers . Let
be the block upper triangular subgroup with blocks of size
. Then
is the Grassmanian of filtrations
such that
, which is a projective variety. For the partition
, we obtain the subgroup of upper triangular matrices, a Borel subgroup of
.
Fix
a maximal torus. Let
be the root datum of
. A
root basis of
is a subset
such that every
can uniquely expressed as
, where
are integers that are all positive or all negative.
There is a canonical bijection between the root bases and the Borel subgroups
that contains
, characterized by
inside the Cartan decomposition of
. The Weyl group acts simply transitively on both sides of this bijection.
. The Borel subgroups
is in bijection with the orderings
of the standard basis
of
, i.e.,
is given by the stabilizer of the flag
. For example,
gives the subgroup of upper triangular matrices
. The corresponding root basis is
and
as desired.
A
based root datum is a tuple
where
is a root basis of the root datum
. So a choice of
gives a based root datum.
A reductive group
is
semisimple if
is trivial. A semisimple group
is
almost-simple if it has no normal subgroup of dimension
;
simple if it has no nontrivial normal subgroup.
An
isogeny of semisimple groups is a surjective homomorphism
with finite (automatically central) kernel. If
is semisimple, we say
is
simply-connected if there is no proper isogeny
;
adjoint if there is no proper isogeny
(equivalently,
has trivial center).
If
is a semisimple group, then there is an ordering-preserving bijection between the elements of the isogeny class of
and the subgroups of
. In particular, the simply-connected group corresponds to the full group and the adjoint group corresponds to the trivial group.
If
is almost simple, we associate to it a graph, the
Dynkin diagram of
. Fix a root basis
. The Dynkin diagram has the vertex set
. For
, let
. Then
and we join
,
with
edges. If
, we decorate this multiple edge with an arrow from
to
if
.
Let
be an almost simple group. The Dynkin diagram of
is connected. If
is another almost simple group, then
and
are in the same isogeny class if and only if they have the same Dynkin diagram.
Let
be a reductive group. We denote by
the group of automorphisms of
as an algebraic group over
. We have an exact sequence
Notice
.
A
pinning of
is a tuple
where
is a maximal torus,
a Borel subgroup,
a root basis of
and
is a basis of
.
Let
be a pinning and
be a based root datum of
. We define
be the automorphisms of
that fixes
and the
set . We define
be the automorphisms of
that fixes
and
. There are natural maps
and
.
- The natural maps and are isomorphisms. Consequently, .
- All pinning of are -conjugate (so all the above splitting are conjugate under the action of ).
Reductive groups over general fields
In this section we assume that is an arbitrary field of characteristic 0. Let be an algebraic group over . Let be an algebraic closure of .
We say
is reductive, semisimple, unipotent, solvable, torus if
satisfies the corresponding property.
Notice acts on with fixed points .
A torus
is called
split if there exists an isomorphism
defined over
(such an isomorphism always exists over
). If
is any torus over
. We define
. This is a free finitely generated abelian group with an action of the Galois group
.
The assignment
defines an (anti-)equivalence of categories between the category of tori over
and the category of free finitely generated abelian groups with a smooth
-action (equivalently, the conjugacy classes of homomorphisms
.)
10/03/2013
We say that a torus
is
maximal if
is maximal. It is a fact that
always contains maximal tori.
A
maximal split torus is a split torus, maximal with respect this property. We way
is
split if
contains a split maximal torus.
We start off with the split reductive groups when we classify reductive groups over general fields.
- Let be a root datum. Then there exists a reductive group and a split maximal torus such that is the root datum of .
- If and be split reductive groups over with the same root datum, then they are isomorphic over .
Let
be a linear algebraic group over
. A
form of
is a linear algebraic group
over
such that there exists an isomorphism
. By the above theorem, any reductive group over
is a form of a split reductive group over
.
So our remaining task is to classify the forms of a split group.
Let be a split reductive group and be any reductive group with . For any , acts on and obtain another . One knows that . This is an example of a 1-cocycle in non-abelian Galois cohomology.
Let
be a group with a continuous action of
(
is endowed with the discrete topology). A
1-cocycle is a map
satisfying
. We say two
1-cocycles are
1-cohomologous if there exists
such that
for all
.
We have constructed a 1-cocycle . Changing to where doesn't change the class of . Therefore we obtain a map between the isomorphism classes of forms of to . Using Galois descent one can show that
This map is bijective.
Suppose is split and fix a pinning defined over (i.e., is split, is defined over and are defined over ). Let be the associated based root datum. Recall (Theorem 13)the pinning splits the exact sequence acts on this exact sequence and one can show that when is defined over , acts trivially on and the splitting is -equivariant. Thus it gives a homomorphism In particular, any form of gives a homomorphism up to conjugacy (which of course does not determine up to isomorphisms because we lose information when passing from to .)
A reductive group over
is
quasi-split if it contains a Borel subgroup (i.e.
such that
is a Borel subgroup).
Let
be reductive groups over
. We say
is an
inner form of
if there exists an isomorphism
such that for any
,
. Equivalently, the associated class
lies in the image of
.
The following lemma tells us that passing to , we exactly lose the information distinguishing the inner forms of the same quasi-split group.
has a unique quasi-split inner form. If
and
are forms of the same split group
, then they have the same quasi-split inner form if and only
up to conjugacy.
We summarize the strategy of classifying reductive groups over general fields:
- Construct the split group given a root datum.
- Classify the quasi-split groups (corresponding to homomorphisms ).
- Classify the inner forms of each quasi-split group.
The example is in order.
If
is a central simple algebra of rank
, we define a group
over
by the functor of points:
(this is a representable functor).
depends on
only up to isomorphism, so
Every inner form of
is isomorphic to
for some
. For example, when
, the group
has two inner forms
and
.
Fix the standard pinning of . The associated based root datum has automorphism group . So there is a bijection between quasi-split (non-split) forms of and quadratic extensions . Define a Hermitian form on by , where . Notice does map to the nontrivial element in , but the choice of is chosen to be compatible with the splitting given by the standard pinning: preserves the standard Borel and the alternating signs are chosen to preserve each basis .
Define the group by the functor of points The group becomes isomorphic to over . Indeed, for any -algebra , we have and the automorphism of induces the automorphism of . It follows that . One can show the upper triangular subgroup of is a Borel subgroup, therefore is quasi-split as desired.
The inner forms of can be constructed as follows: let be a central simple algebra over and be an anti-involution of that restricts to on (e.g., , ). Then each inner form of is of the form
10/08/2013
Automorphic representations on reductive groups
Reference on this section: the article of Borel-Jacquet in Corvallis I.
Let
be a number field and
be a reductive group. Choose an embedding
, then for any place
of
, we endow
the subspace topology from
. For
a finite place, we define
an open compact subgroup of
. If we choose another embedding
, then
for almost all
. We define
to be the restricted product
with respect to
. The topology is the subspace topology from
.
Recall that for any Hausdorff locally compact topological group
, there is a Haar measure on
(Definition
6) unique up to
-multiple. The
modulus character is defined as
is called
unimodular if
is trivial.
If we further assume
is a closed unimodular subgroup. Then there exists a Haar integral
on the quotient space
which is right
-invariant. Again
is unique up to
-multiple.
Denote , a real Lie group. We choose a maximal compact subgroup (which is unique up to conjugacy). Let and .
An
automorphic form on
is a function
satisfying:
- For any , , .
- For any , the function is smooth.
- is -finite, i.e., is a finite dimensional vector space.
- is -finite, i.e., is a finite dimensional vector space.
- There exists an open compact subgroup such that for any and , .
- For any , the function is slowly increasing. A function is slowly increasing, if for one (equivalently, all) embeddings of real algebraic groups, there exists such that for any ,
We say is cuspidal if it further satisfies
- For all parabolic subgroups defined over , for any , where is the unipotent radical of . Notice by the left- invariance, if this condition is satisfied for a parabolic subgroup , then it is satisfied for all parabolic subgroups conjugate to .
We write for the space of automorphic forms on and the subspace of cusp forms.
(Harish-Chandra)
If
, then it generates an admissible
-submodule of
.
An
automorphic representation on
is an indecomposable
-module, isomorphic to a subquotient of
. We say
is
cuspidal if it is isomorphic to a subquotient of
(
is semisimple as the case
).
(Hilbert modular forms)
Let
be a totally real field. Let
be the infinite places. Let
. Then
. We choose
. Recall for any
we defined an irreducible, admissible
-module
(Proposition
6). We choose integers
and consider the cuspidal automorphic representations
of
such that
. These correspond to classical
Hilbert modular forms of weight
.
(Quaternion algebras over )
Let
be quaternion algebra over
. Let
be the associated inner form of
. Recall that for
or
, there exists two isomorphic classes of quaternion algebras over
, the split one and the non-split one. For
, the isomorphic classes of quaternion algebras correspond to finite set of places
of
of even cardinality, where
is the set of non-split places of
.
Suppose is nonempty and does not contain , then is anisotropic modulo center since is anisotropic for every . Moreover, . One can check that cuspidal automorphic representations of such that can be described in terms of holomorphic functions on a compact quotient of : there are no cusps since is anisotropic.
Now suppose contains . Then is still anisotropic modulo center but is compact modulo center. The automorphic representations such that is trivial are in bijection with the -constituents of the space such that
- For any , .
- There exists an open compact subgroup which fixes on the right.
- For any , , (due to the triviality at ).
In other words, these are the functions on a finite set . It turns out these simple-looking functions are very interesting and the following Jacquet-Langlands correspondence is the first case of functoriality:
10/10/2013
Representation theory of -adic groups
Reference for this section:
- Bushnell, Henniart, Local Landlands conjecture for GL(2);
- Cartier, Corvallis I.
To talk about automorphic representations more intelligently, we need to know more representation theory of local fields, both non-archimedean and archimedean. Then Dick Gross will come and tell you about -groups. Afterwards we are going to discuss Galois representations and it relation with automorphic representations, and as promised, the theorem of Chenevier-Clozel on number fields with limited ramification.
Unramified representations
Let be a finite extension of and be an reductive group. We abuse notion and write for the locally compact topological group . Today we will focus on the simplest case: the unramified representations of a unramified -adic reductive group.
is called
unramified if
is quasi-split and split over an unramified extension of
. In other words,
is determined by a homomorphism
that factors through an unramified extension of
.
The nice thing about unramified groups is that they admit distinguished open compact subgroups.
Let
be unramified and fix
a maximal split torus. Let
, then
is a maximal torus (for general
, it is the "anisotropic kernel" of
). We denote by
the maximal compact subgroup.
Let
and
be the diagonal torus. Then
is also the diagonal torus and
.
The
split Weyl group is a constant group scheme over
It acts faithfully on
and
.
(Satake isomorphism)
There exists a canonical isomorphism between the Hecke algebras
, where
is a hyperspeicial maximal compact subgroup of
.
We can assume
after conjugation. We will write down the
Satake transform . Let
be a Borel subgroup containing
(because
is quasi-split,
contains a Borel; a maximal torus is the centralizer of the its maximal split subtorus and all maximal split tori are conjugate, we can conjugate such a Borel to contain
). Let
be the modulus character. Given
, we define
where
is the unipotent radical of
. One can check that it has image in
. It turns out the map does not depend on the choice of
(due to the modulus character factor). For details, see Cartier.
¡õ
Let
be an irreducible admissible representation of
. We say
is
-unramified if
. We say a character
unramified if it is trivial on
.
The previous theorem together with Theorem 3 have the following corollaries.
If
is
-unramified, then
.
The equivalences of the first two and last two are clear. For the equivalence between b) and c), simply notice that
is a group isomorphism.
¡õ
Now we introduce the notion of parabolic induction for general reductive groups and come back to unramified representations in a moment.
Let
be a parabolic subgroup and
be the Levi decomposition. Let
be an admissible representation of
. We define a
-representation
where
acts by right translation.
is admissible.
Consider any open compact subgroup
. We need to show that
is finite dimensional. Since
is projective and hence compact, we can find
a
finite set such that
. Then
is determined by the values
for
. One can check that
. The latter space is finite dimensional as
is admissible by assumption.
¡õ
If
is an admissible representation of
. We define the
normalized or
unitary induction
.
Suppose
is unitary. Then
is also unitary.
We sketch the case
is a character. Then
is unitary means that
. Then
For
, we write
and try to define the unitary structure by integrating
. However,
is not unimodular and there does not exist
-invaraint integrals on the quotient
. Nevertheless, we do have a right
-invariant integral
on the subspace of locally constant functions
such that
. One can check that
using the extra
factor and
. So integrating
does give a unitary structure on
.
¡õ
Now we come back the the situation where is unramified, hyperspeicial, maximal split torus. and a Borel containing . Let be any smooth character.
Define
. This is called a
principal series representation of
. If
is unramified, then
is 1-dimensional. As a consequence,
has exactly one
-unramified subquotient, denoted by
. Conversely, if
is
-unramified, then we get (up to
-conjugacy) an unramified character
via the Satake isomorphism and
.
,
is the diagonal torus,
,
is the standard Borel. Then
and
, where
is the standard cocharacter
and
is the
-th symmetric polynomial in
.
Let
be a classical holomorphic modular forms that is an
-eigenvector for all
with eigenvalue
.
generates an automorphic representation
of
. For
,
is
-unramified for
. Factor the Hecke polynomial
Then the character associated to
via the Satake isomorphism is
One can compute directly that
is irreducible and
. Explicitly,
10/15/2013
Let
be a number field and
be a reductive group over
. For all but finitely many finite places
of
. The group
is unramified and the group
is a hyperspeicial maximal compact subgroup.
(Sketch)
There is an
-torsor
, where
is the quasi-split inner form of
. This torsor has a marked connected component
that is a torsor for
. The assertion that
is quasi-split almost everywhere is equivalent to the assertion that
is non-empty for almost every
.
¡õ
If
is an irreducible admissible representation of
, then for all
, there exists an irreducible admissible representation
of
and an isomorphism
. In particular,
for almost all
(hence is 1-dimensional for almost all
).
See Flath, Corvallis I.
¡õ
Hierarchy of representations of -adic groups
Let us come back to the local situation. Let be a -adic field and be a reductive group. We are going to define several classes of irreducible admissible representations of .
Let
be an irreducible admissible representation of
. Then there is a
central character such that
for any
and
.
See Bushnell-Henniart.
¡õ
We define
, the
contragredient of
as the space of smooth vectors in the algebraic dual
(this definition works for arbitrary smooth representations). If
is
admissible (not necessarily irreducible), then the natural map
is an isomorphism.
Let
be an irreducible admissible representations of
with central character
. Choose
,
. We define the
matrix coefficient , where
is the natural pairing between
and
.
We say
is
square-integrable if
is unitary (i.e.
) and for any
,
,
We say
is
supercuspidal if for any
,
, the function
is compactly supported modulo center.
- If is irreducible admissible, then is square-integrable (resp., supercuspidal) if and only if there exists nonzero , such that is square-integrable modulo center (resp. compactly supported modulo center) and is unitary (resp. no condition on ).
- If is unitary, then is supercuspidal implies that is square-integrable.
- If is square-integrable, then is unitary (i.e., admits a -invariant positive definite inner product).
(Sketch)
- Fix , let be the space of such that is compactly supported modulo center. Then one can check that is a nonzero -invariant subspace, hence .
- Obvious.
- Fix nonzero. We define for , One can check it defines a unitary structure.
¡õ
Let
be irreducible admissible with
unitary. We say
is
tempered if for any
,
lies in
for any
.
So far everything works well for all locally profinite groups. The following theorem needs more from input from the structure theory of reductive groups.
- An irreducible admissible representation of is supercuspidal if and only if there does not exist a proper parabolic and an admissible representation of together with an embedding .
- Any irreducible admissible representation admits an embedding for some and a supercuspidal representation of .
This is a hard theorem: see Casselman unpublished notes on
-adic groups.
¡õ
Local Langlands correspondence for over -adic fields
. A standard parabolic
corresponds to a partition
, where
. Its Levi subgroup
. Therefore every irreducible admissible representation
of
embeds as
, where
is a supercuspidal for
. A special case we have seen is that any unramified representation
is a subquotient of
, where
is an unramified character.
There is a nice interpretation in terms the local Langlands correspondence for proved by Harris-Taylor and Henniart. The local Langlands correspondence for is a bijection between
- isomorphism classes of irreducible admissible representations of ;
- conjugacy classes of semisimple homomorphisms (i.e. decomposes as direct sums) such that is algebraic, where is the Weil group of .
is characterized abstractly by some identities relating to their -functions.
If
is the unramified subquotient
, then
is trivial on
, unramified on
and sends a uniformizer
to
.
The local Langlands correspondence
restricts to a bijection between
- classes of supercuspidal representations.
- classes of irreducible representations (trivial on the factor).
Suppose
, and
. Let
, it is a supercuspidal representation of
. Let
, then
is indeed a subquotient of
.
To summarize: building irreducible admissible representations of from supercuspidal representations of Levi subgroups mirrors taking direct sums of irreducible Langlands parameters .
Let
,
and
be irreducibles. Then
is a subquotient of
. One can view the
-factor a way of labeling different subquotients.
Let be any reductive group. There is a canonical square-integrable representation of , the Steinberg representation that we are going to construct now. Let be a minimal parabolic, define
- The subrepresentations are in bijections with parabolic subgroups : .
- Let be the quotient of by the span of , . Then is irreducible and square-integrable.
If
. Then
is the unique homomorphism trivial on
and restricts to the unique
-dimensional representation of
. Thus
is a subquotient of
. If
. Then we have an exact sequence
This exact sequence does
not split and gives an example of unramified principal series representation (as
is unramified) that has a ramified unitary quotient and a trivial subrepresentation. One also knows that
is non unitary since any unitary admissible representation is semisimple (Lemma
3).
Let
be the cuspidal automorphic representation of
associated to an elliptic curve
. Then
has multiplicative reduction at
if and only if
is an unramified twist of
.
Very recently Gross-Reeder constructed a class of
simple supercuspidal representations. For example, consider
,
and
. Let
. It is a character and indeed
is a supercuspidal representation.
10/17/2013
Representation theory of real reductive groups
Reference for this section: Wallach in Corvallis I.
Let be a reductive group . We use the usual notation: , , a maximal compact subgroup. , .
-representations
A representation
of
is a (separable) Hilbert space
and a homomorphism
to the group of bounded invertible linear operators such that
- then map is continuous.
- for any , is unitary (i.e. an isometry).
We say
is
irreducible if there is no nontrivial closed
-invariant subspace of
. We say
is
unitary if for any
,
is unitary.
Let us recall the representation theory when is compact
When is compact, there is a unique -conjugacy class of maximal tori (so is several copies of ). Fix a maximal torus and be an associated root datum. Then the natural map is a bijection. Let be an irreducible representation of . Then as a sum of weight spaces. The map is an isomorphism, so we can view the sum as over . In particular, is invariant under , hence under .
If
and
be the diagonal maximal torus. So
,
and
is the usual diagonal torus. The theorem then parametrizes the equivalence classes of irreducible representations of
by tuples
,
.
-modules
Let be any reductive group over . There is a unique -conjugacy class of maximal compact subgroup (notice this is not true over -adics, cf., Example 16).
,
.
,
.
Let
be a representation of
. By the Peter-Weyl theorem,
where
are irreducibles. We say
is
admissible if each isomorphism classes of irreducibles representations of
appears only finitely many times. It is easy to see that if
is admissible, then the subspace
of
-finite vectors is simply the usual direct sum
For
, we define
. If this exists, then we say
is
differentiable. We say
is
smooth if for any
and any
,
exists.
Hierarchy of representations of real reductive groups
Let
,
be two admissible representations of
. We say they
infinitesimally equivalent if there associated
modules are algebraically equivalent.
Let
is an admissible representation of
. A
matrix coefficient of
is a function of the form
, for
. It is a
-finite matrix coefficient, if
and
are further
-finite vectors.
Let
be an irreducible representations of
with unitary central character. We say
is
square-integrable if its
-finite matrix coefficients are square-integrable modulo
, where
is the center as an algebraic group. It is
tempered if its
-finite matrix coefficients are in
for any
. The square-integrable representations are also called
discrete series representations since they occur discretely in the unitary dual.
The Harish-Chandra isomorphism
The center of the universal enveloping algebra is isomorphic to a polynomial algebra in generators, where is the rank of (= the dimension of a maximal torus). How does one prove it?
We change notion for convenience: let be a reductive group over . Fix a pinning of .
Let
. Then
for any simple root
. We have
.
We define
to be the projection along
. The
Harish-Chandra homomorphism is defined to be the composite
.
(Harish-Chandra)
The map
is an algebra homomorphism, independent of
, and defines a canonical isomorphism
, where
acts on
in the natural way.
10/22/2013
Consider
and
. We define the Casmir element
, where
,
,
. One can directly check that
. We claim that
. Since
in
, we can rewrite
. Fix the root basis
, where
. Then
is a basis of the
-root basis. Hence
. Also
, hence
. So
,
. Therefore
The Weyl group
and acts by
and thus
. Hence
. By the theorem, we know that
.
Now we come back to the situation that
is a reductive group over
. Let
be an irreducible admissible
-module. A version of Schur's lemma says that every element of
acts as a scalar on
. Therefore it defines an algebra homomorphism
, the
infinitesimal character of
. This does not determine the representation
uniquely but does tell a lot of information: e.g., the infinitesimal character of an automorphic representation knows about the Hodge-Tate weights of the associated Galois representation.
For
, we define
by composing
and
. It is a fact that every homomorphism
arises in this manner and
if and only if
are in the same
-orbit.
Square-integrable representations of real reductive groups
Assume is semisimple group over for simplicity in this section (everything said below are true for any reductive group after appropriate modification).
has a compact inner form
, therefore
has discrete series. On the other hand, for
,
has no compact inner form (there are only two division algebra over
!), thus has no discrete series.
We write
, the
unitary dual, for the set of unitary equivalence classes of unitary irreducible admissible representations of
. We write
for the set of discrete series representations.
Assume is non-empty. Then by the previous theorem, there exists a maximal torus and a maximal compact such that and is compact.
The
real Weyl group is defined to be
.
naturally embeds into the
complex Weyl group .
We say
is
regular if
for any
. Notice the regular condition is invariant under the action of
.
We have the following nice parametrization of square-integrable representations.
(Harish-Chandra)
- If is a unitary square-integrable representation of , then has infinitesimal character for some regular.
- There exists a bijection between the square-integrable representations of with infinitesimal character and the set of -orbits inside . In particular there are such representations.
Let
be the unitary group of the Hermitian form
, where
. The subgroup
of determinant 1 is a semisimple group over
, which is a form of
and an inner form of the compact group
. A compact maximal torus in
is the diagonal torus. A maximal compact subgroup is
. We have
and
. The packet of square-integrable representations with same infinitesimal character then has
elements.
Representations of
Let , . We have a maximal torus such that . We have and . Therefore the discrete series representations of fall into packets of 2 elements, parametrized by the -orbits on the regular elements .
Let be the diagonal split maximal torus, , (the connected center of ), the standard Borel and the unipotent radical. Then we have and the Langlands decomposition . The characters of are then indexed by , i.e. . The parabolic induction in this case gives a representation of .
Consider the space
of smooth functions
such that
, for
,
. Recall the
Iwasawa decomposition . Therefore
is uniquely determined by its
restriction on . We define an inner product on
by
We define
to be the Hilbert space completion of
.
10/24/2013
The trace formula for compact quotients
Announcement: Dick Gross will tell us about -groups next Thursday (Oct 31). There will be no class on Nov 7.
The trace formula is a good tool for constructing interesting automorphic representations. We will talk about the trace formula for the compact quotients today and the simple trace formula for non-compact quotients next time.
Let
be a (separable) Hilbert space. We say a linear operator
is
Hilbert-Schmidt if for some (equivalently, any) orthonormal basis
the sum
is convergent. We say
is
of trace class if there exists Hilbert-Schmidt operators
,
such that
.
Let
be a Hausdorff
compact measure space and
is a continuous function, then we define
by the formula
by integrating the kernel function
, then one can easily check that
is Hilbert-Schmidt (by writing it down using an orthonormal basis).
Now let be a unimodular locally compact Hausdorff topological group. Let be a discrete cocompact subgroup.
and
.
and
a discrete cocompact subgroups, e.g., from a quaternion algebra over
or from a compact Riemann surface uniformized by the upper half plane.
Let and . Then is a unitary representation of under the right translation.
Choose
a continuous function with compact support. We can turn this function into an operator on
by defining
by
Then
is given by integrating over
the kernel function
on
:
- For any , is Hilbert-Schmidt.
- Define . Then .
- Define the convolution on by Then .
We can decompose
, where each
is finite and
is the set of unitary equivalence classes of irreducible unitary representations of
.
If
is of trace class, then
Assume that
(in general, we can write
, a linear combination of two self-adjoint functions). We can choose orthonormal eigenvectors
of
forming an orthonormal basis of the subspace
. These functions
are continuous as they are the images of
. We can write
for
, where the sum converges in
. Write
be the truncated sum of
up to
. Since
is of trace class, we know that
. We have
and
since
in
.
¡õ
The trace formula relates two different expressions (the geometric side and the spectral side) for whenever this makes sense.
The geometric side is given by (using the previous lemma)
Here means the conjugacy classes in . is the centralizer of in , is the centralizer of in . The quotient measure makes sense since is unimodular.
The spectral side is much simpler at this stage:
If
is of trace class, then
where
and
.
Now assume is a number field and is a semisimple anisotropic (= contains no nontrivial split torus) group. In this case, the quotient is compact.
Let
be the space of locally constant/smooth and compactly supported functions. By a nice theorem of Dixmier-Malliavin, every function
is a (finite sum of) convolutions (this is trivial on
by convolving an indicate function on the support, but is far from trivial on
). In particular
is of trace class for such a function
.
- Let be a maximal compact subgroup. If is an irreducible unitary representations of . Them the submodule of -finite vectors for (any compact open subgroup) is an algebraically irreducible admissible -module.
- The above assignment defines a bijection between the unitary equivalence classes of irreducible unitary representations of and the isomorphism classes of unitary irreducible admissible -modules.
- The above assignment restricts to a bijection between the unitary equivalence classes of irreducible representations which appear in and the isomorphism classes of automorphic representations of .
See Flath in Corvallis I.
¡õ
10/29/2013
The simple trace formula
References for this section:
- Henniart, Mem. Soc. Math. France 1984;
- Arthur, CJM 1986;
- Arthur, JAMS 1988.
In this section we let be a number field and be a semisimple group (it is easy to extend the results below to the case where is reductive).
Recall form last time that if and is anisotropic, then we gave a formula expressing in two ways The spectral side sums over (countably many) automorphic representations of . The geometric side sums over the conjugacy classes of .
Such a formula does not exist if is not anisotropic (e.g., a group as simple as ). The two main problems are
- does not decompose discretely as the Hilbert direct sum . There exists a certain continuous spectrum.
- The kernel function on is no longer integrable. The operator is no longer of trace class.
Here are two possible ways out:
- Describe the continuous spectrum and truncate to get a well-defined expression. This was done by Arthur after incredible amount of work and the formula thus obtained is called the Arthur trace formula.
- Adopt some simplifying assumptions on the allowable test functions . We shall consider this direction in the sequel.
We define the
cuspidal subspace as the subspace of the functions
such that for all parabolics
defined over
, the integral
for almost every
. We only require "almost every" since there is no reason the integral always makes sense.
- The subspace is closed, -invariant and decomposes discreetly as a countable Hilbert direct sum of subrepresentations, each appearing with finite multiplicity. For , , the restriction of on , is of trace class.
- The assignment , where is the -finite vectors in , gives a bijection between the set of unitary equivalence classes of irreducible subrepresentations of and the set of cuspidal automorphic representations of .
The proof Theorem 32 is much easier than Theorem 31. We shall sketch a proof of Theorem 32.
(Sketch)
The image of
.
This only uses the assumptions a) on
:
is a matrix coefficient of a supercuspidal representation. We need to use: if
is a supercuspidal matrix coefficient, then for any parabolic
defined over
, we have
for any
. We take
, then
Choose a parabolic
defined over
. To check the cuspidality, we need to compute the integral
Now
is compact and
is compactly supported, so we can reverse the order of integration to obtain
One can choose the measure on
to be a product measure
, the assumption on
shows that the contribution from the
-factor is zero. Hence the above integral itself is zero.
¡õ
This lemma implies that is of trace class and . One can then show that the kernel function is integrable along and this integral equals to .
We need another lemma which is also easy to prove, though may take us too far afield.
The function
has compact support on
.
This lemma uses the assumption b) on
. The proof uses the reduction theory of Arthur. Morally speaking, the elliptic classes does not end up in the cusps. See Gelbart, Lectures on the Arthur-Selberg trace formula, for an example for
.
¡õ
Consequently, one has The same manipulation as in the compact quotients is now valid and lead to Theorem 32.
¡õ
Here is one application of Theorem 32.
Let
be a semisimple group over a number field
. Let
be a place of
,
a supercuspidal representation of
. Then there exists a cuspidal automorphic representation
of
such that
.
(Sketch)
Use Theorem
32 with
, where
is a matrix coefficient of
and other
's are arbitrary. It suffices to show that
If this holds, then there exists at least one cuspidal automorphic representation
such that
. But if
is any irreducible admissible representation of
and
, then
(one can write an explicit map from
to
). To show the above sum is nonzero, we look at the the finitely many terms on the geometric side. If the measures are chosen appropriately, then the orbital integral
factors as a product of local orbital integrals
. One can manage to choose
such that exactly one class
contributes to the geometric side and
.
¡õ
10/31/2013
Langlands dual groups
This is a guest lecture by Dick Gross. Notice the notation is different sometimes.
Reference: Casselman, Survey on -groups.
For each reductive group over , we are going to associate a complex Lie group . For a torus, one simply switches the role of the character group and the cocharacter group .
For a general reductive group , recall that one defines the roots using a torus by looking at the action of on ; one then defines the coroots using a -triple associated to the roots. This gives a natural bijection between the roots and coroots and under the natural pairing. The root datum classifies reductive group over algebraically closed field. The simple reflections preserves hugely restricts the possibility of the root datum and the classification boils to the case of rank 2 root system , , and .
The problem of this classification is that the natural map is not injective. For example, the elements acts non-trivially on . Even worse, is not surjective:
Consider
. Then
, where
takes a diagonal element to its
-th diagonal entry;
, taking
to a diagonal element
;
with root basis
. The coroot
. The sublattice
has corank 1. The Weyl group is
and
. This is not all
because
is always an automorphism of
! It turns out to be the case
.
Another extremal case is that
is a torus of dimension
, then
but
!
Now choosing a Borel subgroup (these are permuted by simply-transitively) gives extra structure: the set of positive roots and the root basis consisting of simple roots. The Weyl group no longer acts on this based root datum . The theorem is that
.
One can not lift the action of to an action of in a natural way: these is no canonical way to split the sequence but one can lift elements of ! The group preserving and is which is smaller than but still too large. The idea is to require that it also preserves a pinning (if you imagine that Borels are like the wings of a butterfly, one "pins" it down): a basis for each . Now acts transitively on the set of pinning, and the stabilizer is exactly . The upshot is that there is no inner automorphism preserving the based root datum.
(Chevalley)
and
.
One can do the same thing for groups which are quasi-split but not necessarily split. Suppose is split over . The acts on . Chevalley noticed that switching the role of gives you another based root datum with the same automorphism group .
For
, the
and
(since they have to product to 2). The dual root datum gives that of
. The dual root datum can be even more wired in general, for example
.
Chevalley noticed this dual operation but didn't know what to do with it. Langlands realized what to do with it: he called it the dual group , a connected reduction group over (the choice is a bit artificial) up to isomorphism with the based root datum . In particular, the Galois group acts on .
Langlands generalized this to define a group that is not necessarily connected.
The
Langlands dual group , where
acts through pinned automorphism of
. We will later see taking this semidriect product is a bad idea, but this is the first thing you should do.
For
,
.
For
,
. What is this group? It is a subgroup of
(when
is even) or
(when
is odd). Take the Siegel parabolic
(when
is even) or
stabilizing the maximal flag of isotropic subspaces, then the normalizer of the Levi in this Siegel parabolic is exactly the
!
A
Langlands parameter for a local field
is a homomorphism
, up to
conjugation by
(to be modified later: one shall use the Weil group
instead
so that one can send the Frobenius to any semisimple element (not necessarily of finite order); one shall need an extra
-factor to account for the monodromy operator which is unipotent).
Let
be the stabilizer of
. We define
. It is a finite group attached to the Langlands parameter.
is trivial for
, but can be nontrivial for other groups.
The local Langlands conjecture says
There is a bijection between the classes of
, where
is a Langlands parameter and
is a representation of the finite group
, and the isomorphism classes of irreducible admissible representations of
.
Consider
over
,
. The
. Let
be the reflection around two axes. Its normalizer is
and its centralizer is itself. By Kummer theory, there is a unique
-extension of
since
. One obtains a unique (up to the
-conjugation) Langlands parameter
and
. It should parametrize four representations of
. What are they? All these representations are depth zero supercuspidal constructed by Deligne and Lusztig. There are two maximal compact subgroups up to conjugacy of
:
and its conjugate by
. These four representations are exactly the induced representations from the two half discrete series representations of dimension
of
! The case
is already interesting:
is a double covering of
of order 24, the two half discrete series representations are of dimensional one, i.e., the two cubic character of
.
11/05/2013
We are back to Jack's notation.
References:
- Borel, Corvallis II. It includes everything (expected to be true) about -groups;
- Langlands, Problems in the theory of automorphic forms (historical document;
- Gross-Reeder, From Laplace to Langlands.
Let be a field of characteristic 0 and . Let be a reductive group over . Let be the bases root datum of . Then the Galois action on the root datum of induces homomorphism (which only depends on the quasi-split inner form of ).
We observed that by swapping the role of roots and coroots is still a based root datum and . We let be the split reductive group over (sometimes we also use depending on the situation) with the based root datum equipped with a pinning giving rise to .
Define
, where
acts via
on
. If
is a Galois extension such that
is trivial, people also use the definition
.
Langlands parameters
Local Langlands conjecture
The introduction of the -group allows us to state the Langlands conjecture. Assume now is a -adic field, or .
If
or
, a
Langlands parameter is a semisimple continuous homomorphism (i.e., a direct sum of irreducible ones, for any representation of
)
such that
is the usual map. As the
-adic case, we define similarly the notion of equivalence.
Let be the classes of Langlands parameters of and be the set of isomorphism classes of irreducible admissible -module, where and is a maximal compact subgroup.
(Local Langlands conjecture)
There is a natural partition
into finite disjoint sets
. If
is quasi-split, every
is non-empty. The set
is called a
-packet.
Of course this conjecture has no content without assuming extra condition characterizing the -packets . The following cases are known:
- When , the conjecture is known and the set can be written down explicitly using the parametrization of as a starting point. This is due to Langlands.
- If is -adic and is a torus, then the correspondence exists and can be essentially constructed from local class field theory. If , this is nothing but local class field theory.
- When is -adic and . In this case, all the sets has size one and gives a bijection between and . This is due to Harris-Taylor, Henniart. Scholze recently gave a new proof. The correspondence is characterized by some compatibility condition arising from the theory of -functions due to Henniart. Henniart showed there is at most one of such bijection. Harris-Taylor proved the existence of such a bijection satisfying this characterization.
- When is -adic and is a quasi-split classical group. The correspondence exists and is characterized by comparison with due to the recent work of Arthur and Mok. This is established using the fact that these groups are twisted endoscopy groups of and the method of twisted trace formula (including the fundamental lemma).
- If is -adic and is unramified, then there is a natural correspondence between the unramified elements in and the unramified -packets (namely these factor through ).
Unramified local Langlands correspondence
Let be a -adic field and be an unramified reductive group. Fix a hyperspeicial maximal compact subgroups.
There is a canonical bijection between
such that
and unramified parameters
.
Let
be a maximal split torus. The centralizer
is a maximal torus of
(Definition
52). The group
is a constant group scheme over
and acts faithfully on
. Let
be the minimal extension splitting
. Then
is unramified. Let
be the arithmetic Frobenius and
be its image. The
contains the subset
, which is normalized by
. If
is an unramified Langlands parameter. Then it is determined by
, i.e., semisimple
-conjugacy classes in
.
On the other hand, the unramified represetnations are parametrized by by the Satake isomorphism (Corollary 6).
Since acts on , hence on by functoriality, hence can view . Let be the inverse image of in . A bit work shows that both are in bijection with .
¡õ
When
is split,
,
and
. When
,
is simply the
-conjugacy classes of parameters
. The unramified parameters simply correspond to semisimple conjugacy classes in
, i.e.,
-orbits of diagonal matrices. On the other hand, an unramified representation
is a subquotient of a parabolic induction
, where
are unramified characters, determined up to
-conjugacy. The bijection is simply
.
Global Langlands functoriality conjecture
Let be a number field and be a reductive group. Recall that for almost all places of , the group is unramified. If is an irreducible admissible representation of , then for almost all , is an unramified representation. Choose for every place of an algebraic closure and an embedding extending . This induces an inclusion , hence a map .
For any irreducible admissible representation
of
, the unramified local Langlands correspondence gives for almost all places
a
-conjugacy classes
. We call the collection of elements
defined for almost all
the
Satake parameters of
.
(Global Langlands conjecture)
Suppose
is an admissible homomorphism and
is an automorphic representation of
. Assume
is
quasi-split. Then there exists an automorphic representation
of
such that
for almost all places
.
The are endless interesting examples of this conjecture by taking different and .
When
is a quasi-split inner form of
and
is the identity, the conjecture says that there is an automorphic representation
of
such that
.
When
(Example
13 ) and
. This is the Jacquet-Langlands correspondence. You may not always go back from
to
due to the local obstruction.
When
and
. A homomorphism
gives gives an admissible homomorphism
. The conjecture says that there exists an automorphic representation
of
such that
is the conjugacy class of
. This is known as the
strong Artin conjecture.
11/12/2013
Global Langlands correspondence
References for this section:
- Clozel and Milne, Ann Arbor volumes (the article by Clozel is especially relevant);
- Buzzard and Gee, On the conjectural relations between automorphic representations and Galois representations (a more modern treatment).
There are Galois representations which do not correspond to automorphic representations (and vice versa). We have to make restriction on both sides in order to make sense of the global Langlands correspondence. This requires the notion of "algebraic" automorphic representations and "algebraic" Galois representations.
Algebraic Galois representations
Let be a number field. Fix an algebraic closure . For a place of , fix an algebraic closure of . Choose an embedding extending the embedding . This induces an map , whose image is the decomposition group at .
For a finite set of finite places of , let be the maximal unramified extension of away from . Write . For , the map factors through . and we write for the image of the geometric Frobenius, i.e., the inverse the of the arithmetic Frobenius (which acts on the residue field by ).
Let be an reductive group. Let be a prime and be an algebraic closure of . Let be a finite Galois extension which splits . We view as the dual group defined over and , a linear algebraic group over with connected component . We endow with its natural -adic topology induced from some embedding (it is not locally profinite because is too big).
A continuous homomorphism
is
admissible if the composite map
is the natural projection.
- We say that a continuous homomorphism is algebraic if
- there exists a finite set such that factors through (i.e., is unramified almost everywhere).
- For any place of , the restriction is de Rham (the -analogue of being "potentially semistable" at places ).
- We say an admissible homomorphism is algebraic if for any algebraic representation , is algebraic. Equivalently, is algebraic for one faithfully representation .
Let
be a smooth geometrically connected projective variety over
. The
-adic etale cohomology groups
are finite dimensional
-vector spaces on which
acts. The associated Galois representations
are algebraic. To prove that it factors through
, one can apply the proper smooth base change theorem after constructing a proper smooth model of
away from
. To prove that it is de Rham, one needs Faltings' comparison theorem.
When
is the elliptic curve,
is dual to
. After choosing a basis, we obtain a 2-dimensional Galois representation
. When
is a place of good reduction,
is unramified at
and
is an integer related the number of points of
mod
.
Algebraic automorphic representations
Let be a number field and be a reductive group. Fix a place of , induced by an embedding . Then is a real Lie group. Let be the complexified Lie algebra. Choose a maximal compact subgroup. Choose a maximal torus and write , .
Recall that we have a Harish-Chandra isomorphism (Theorem 24). Also recall that if is an irreducible admissible -module, then there exists such that the infinitesimal character of is equal to , obtained by . This determines up to -conjugacy. (Definition 73).
Notice has a natural integral lattice given by given by .
- We say is -algebraic if lies in .
- We say is -algebraic if , where is the half sum of the positive roots for some root basis. One can check this definition is independent of the choice of the root basis.
- If is an automorphic representation of . We say is -algebraic (resp. -algebraic) if for any , is -algebraic (resp. -algebraic).
Consider
. If
is an automorphic representation of
, then for each
we obtain
. If
is a Galois representation, then for each
we obtain a
Hodge-Tate-Sen weight lying in
. These weights all vary continuously. But if
is de Rham, then the Hodge-Tate-Sen weights lie in
. The weights at
can be read off from the Hodge structure of the corresponding motive. People guess these are related to the Hodge-Tate-Sen weights exactly when the de Rham condition is satisfied. There do exist Hodge-Tate but non de Rham Galois representations (e.g., coming from
-adic modular forms), but these don't come from geometry, see the end of the paper of Mazur-Wiles for an example.
Fix
and
. Assume given
an eigenform for
,
with eigenvalue
. We associated
an automorphic representation
of
. For
,
, where
are unramified characters such that t
. Let
Let
for any
. These
are also cuspidal automorphic representations, which we can view as being associated to
too. Sometimes it is convenient to normalize
to be unitary, i.e.
.
Notice , where and , . An algebra homomorphism is induced by an element of if and only if there exists such that , , i.e., . On the other hand, the has infinitesimal character and .
Thus is -algebraic if and only if ; -algebraic if and only if . has a twist which is both -algebraic and unitary if and only is odd. In particular, it explains the case in Remark 82.
Let
be a totally real field of degree
. Let
be a cuspidal Hilbert modular form of weight
, where
. One can associate
a cuspidal automorphic representations
which is defined up to a character twist. When does
have an
-algebraic twist? Let
be a real place of
, then
. The local theory at
is the same for
. Suppose
is
-algebraic, then
,
. Since
is cuspidal, there exists
, such that
is unitary (this is true for any cuspidal automorphic representations on general reductive groups). So
is independent of
. In particular,
is independent of
. We conclude that one can lift
to an
-algebraic
only if the parity of
is independent of
. In fact one can show this is also sufficient (see Clozel in Ann Arbor).
Can associate to each an such that has infinitesimal character.
11/14/2013
Global Langlands correspondence
Fix a prime . Choose an isomorphism (One expect everything to be defined algebraically, so this choice not essential. If we know everything is defined over , it is enough instead to fix something weaker: two embeddings and ) (see Remark 90). To state the general conjecture, we'd better fix such an isomorphism .
Let be an reductive group over a number field . Suppose is an automorphic representation of .
Suppose
is
-algebraic. Then there exists a finite set
places of
containing infinite places, places
and the places at which
,
are ramified, and an algebraic Galois representation
satisfying:
- is unramified outside ;
- For any , (Definition 89).
In the case , we have the following more precise conjecture.
If is a finite place of , we denote the Artin map from local class field by , normalized so that , where is the geometric Frobenius. We denote for .
When is a Hecke character -algebraic? We need to look at the infinite components of .
If is a real place, then is is given by , where , . The condition of -algebraicity asks that the differential of agrees with the differential of an algebraic character of . That is to say, (and no condition on ).
If is a complex place, then . It has the form , where , and the symbol is defined formally so that . We are supposed to think of as a real Lie group. Let , it is a rank 2 torus over whose functor points is for any -algebra . In particular, . The -algebraicity condition says that the differential of agrees with the differential of an algebraic character of , i.e., for . That is to say, .
These -algebraic Hecke characters are exactly the character of type already introduced by Weil.
Here is a compact way of describing an -algebraic character : there exits integers indexed by embeddings such that , where and , where is the place of induced by .
The following theorem verifies Conjecture 5 for .
Fix a prime
and
. Let
be an
-algebraic character. Then there exists a unique representation
satisfying the condition of Conjecture
5. Explicitly, it is given by
Conversely, every algebraic representation
arises in this way from a unique
-algebraic character
.
We state partial results (automorphic to Galois) toward Conjecture 5 for over CM fields.
A number field
is called
CM if there exists
such that
, for any embedding
. Let
, then there are only two cases:
- is totally real;
- is totally real and is a totally complex quadratic extension.
Local-global compatibility
Now suppose is any number field and is a cuspidal -algebraic automorphic representation of . Suppose is known to exist. The local-global compatibility should give at ramified places, where is the local Langlands correspondence. When , one can say exactly what should be using Grothendieck's -adic monodromy theorem (see Tate, Number theoretic background in Corvallis II).
Back to the situation in Theorem 38, the local-global compatibility is known to hold due to Taylor-Yoshida for the case a) and Caraiani for the case b).
We now state a special case we shall need for the application of Chenevier-Clozel on number fields with limited ramification.
Fix a finite place
of
. Suppose
is unramified if
and
is supercuspidal. Then
is irreducible. The representation
is unramified at all
, and
.
11/19/2013
References for this section:
- Chenevier, Number fields with given ramification (Compositio)
- Chenevier-Clozel, Corps de nombres peu ramifies (JAMS)
Number fields with given ramification
The remaining of this course will be devoted to the application of Chenevier-Clozel on number fields with prescribed ramification, as promised in the first class. To put things in context, we first recall the following classical result.
Let
a prime and
be a finite extension. Then there exists an extension
such that
and
as
-algebras where
is the unique place of
over
.
Choose
be a primitive element (i.e.,
). Let
be its (monic) minimal polynomial. One can choose
such that
for any
and
. By Krasner's lemma, if
is small enough, then
has a root in
and
. We simply set
. Then
.
¡õ
Choose algebraic closures
of
and
of
and an embedding
. Then the natural map
is injective.
We would like to control the ramification at almost all primes. Consider a finite set of primes and a prime . Let the maximal unramified subfield of unramified outside .
We write
for the property that the natural map
is injective. Equivalently, if
is a finite extension, then there exists a number field
unramified outside
, a place
of
above
and an embedding
of
-algebras.
Chenevier-Clozel proved that this property is true as long as contains at least two primes.
(Chenevier-Clozel)
holds if
and
are distinct primes.
More generally,
Let
is any number field,
be a finite set of finite places of
and
. Write
similarly for the property that
is injective.
We are going to construct interesting automorphic representations with prescribed level, whose associated Galois representation helps us to attack this algebraic number theoretic problem .
Let
be integers and
be a prime. Then the set of primes
such that the order of
in
is divisible by
is
infinite.
Let
be a finite extension of
. Suppose
acts trivially on
(the tame quotient of the inertia subgroup
) by conjugation. Then
.
If
, then by Kummer theory, its action on
is the multiplication by
, where
is the unramified quotient and
is the size of the residue field of
. If this action is trivial, the image of
in
is trivial for all primes
. By the previous lemma applying to
, we know that
, where
is any prime power. Hence
and
.
¡õ
We can rephrase this lemma in the language of Galois theory.
Let
be a finite extension of
. Let
be a (possibly infinite) Galois extension. If
, then
.
Let
and
. They are closed normal subgroups of
. The assumption shows that
. Hence
. In particular,
commutes with
, hence by the previous lemma,
, which is impossible unless
.
¡õ
Let
be a number field and
be a finite set of finite places of
,
. Choose
a prime, an isomorphism
and an embedding
extending the canonical map
. Suppose for
every irreducible continuous representation
there exists a continuous representation
such that
Then the property
holds.
By the previous corollary, it is enough to show that
(so the completion of
is
). Fix
a finite Galois extension inside
, we need to show that
. Let
be the regular representation of
. Applying the hypothesis of the lemma to each irreducible representation
(of
, we obtain a representation
such that
. Let
. Then
. Since the regular representation is faithful, by Galois theory, we obtain that
: indeed, we have
and
, by construction
.
¡õ
Let
be totally complex CM field with its maximally totally real subfield
. Let
be the unique nontrivial element. Fix a prime
, a finite place
of
not dividing
and a finite set
of finite places of
such that the places
and
are contained in
. Suppose that for all integers
and for every supercuspidal representation
of
, there exists a cuspidal conjugate self dual regular
-algebraic automorphic representation
such that
- For any of , is unramified;
- there exists an unramified character such that .
Then holds.
We will show that the conditions in the previous lemma hold. Fix
and a continuous irreducible representation
. We would like to realize it globally. Let
be a supercuspidal representation of
(Example
22). Let
be an automorphic representation of
satisfying the assumption. Then
is a cuspidal regular
-algebraic automorphic representation of
and has associated Galois representation (Theorem
38)
satisfying
- is unramified at all places of as is unramified and .
- . This follows from the local-global compatibility and the compatibility of local Langlands correspondence with twisting by characters. Notice is unramified so the twisting disappears when restricting to the inertia subgroup.
¡õ
We won't prove the full . Instead, we will prove an earlier result of Chenevier:
- Let be a totally complex CM field and let be a place of split over . Let and assume . Then holds.
- Let be a prime and be an integer such that is the discriminant of a quadratic imaginary field in which splits. Let be the set of places dividing . Then holds.
11/21/2013
Base change from unitary groups
References:
- Mok, Endoscopic classification of representations of quasi-split unitary groups;
- Clozel et. al., On the stabilization of the trace formula (Paris book project)
In view of Corollary 9, we would like to construct automorphic representations with prescribed local component. In some sense the only way of doing this is to use the trace formula. The problem is that, unlike the supercuspidal representations at finite places, the -algebraic representations of are not isolated in the unitary dual of and hence is not easy to pick out by choosing suitable test functions. But they are isolated in the subset of conjugate self-dual representations of . So one can use the twisted trace formula which picks out only conjugate self-dual ones. This is what Clozel used in proving . We will take a different approach using functoriality (base change from a unitary group).
Let be a number field and be a quadratic extension with the nontrivial element . Let be a unitary group associated to a non-degenerate Hermitian form on . Write , . So is the reductive group over with functor of points . It is an outer form of , split over .
If is a place of above a place of . There are two cases:
- is split in , then . Hence . Projecting to the first factor shows this is isomorphic to . Namely, (though this isomorphism depends on a choice of the place ).
- is inert or ramified in , then is a "true unitary group", which becomes split only after extension of scalars to .
(See Mok for details)
Notice for any
-algebra
,
So
. One can then figure out the
. To get a map
, we write down an admissible homomorphism between the
-groups:
, given by
,
(one can check that it is admissible). To get a map
, starting with the parameter
. Then
is a pair of parameter
. The map is simply
. See Mok for the proof of the injectivity (resp. bijectivity) between the Langlands parameters.
¡õ
It follows that we have an injection . Since the local Langlands correspondence for is bijective, if we also know the local Langlands correspondence for , then we obtain a map . This map is called the local base change when it exists. The following cases are known to exist:
- When is split in , we had an isomorphism and this map is simply .
- When is inert in and is unramified, this map is explicitly described by Minguez in the Paris book project.
- When is archimedean.
The functoriality in this special case says the following:
(Functoriality for )
Let
be an automorphism representation of
. Then there exists an automorphic representation
of
satisfying: for
in the previous above cases,
is given by the local base change applied to
.
By the theory of Eisenstein series, if
is not cuspidal, then for any place
of
,
is a subquotient of a parabolic induction from a
proper Levi subgroup (see Langlands supplement to Corvallis I). By the assumption,
is supercuspidal, which is not of the form, hence
itself is cuspidal. In particular,
and
are also cuspidal. Now by strong multiplicity one for
cuspidal automorphic representations of
, one only needs to check that
and
are isomorphic for almost all places
. This can be checked by the construction of the base change. For example, in the second case (
is inert and
is unramified), then
has a parameter
. The parameter for
is
, so the parameter for
is
and the parameter for
is
(by the compatibility of the local Langlands correspondence for
with the passage to the contragradient). But
, where
is a lift of
and
is of the form
. A calculation shows that these two parameters agrees
up to conjugation. (c.f., Remark
101).
¡õ
The existence of the base change is the content of the next theorem.
For the existence of
, see Mok. We already know that
is cuspidal and conjugate self-dual. It remains to check the regularity and
-algebraicity at
of
. The square-integrable representations of
,
is parametrized by their infinitesimal characters which came from regular elements
. If a
representations
is square-integrable, then
is regular and
-algebraic (Theorem
26). One then deduces the properties of the base change of
by calculating the infinitesimal character under base change.
¡õ
To summarize, to prove Theorem 42,we are reduced to, by the previous theorem and Corollary 9, the following theorem (which gives more than we needed as input for Corollary 9).
Let
be a number field and
be a reductive group. Suppose that for any
of
,
has compact center and
has square-integrable representations (this implies that
is totally real). Fix a finite place
of
and a supercuspidal representation
of
and an open compact subgroup
. Then there exists an automorphic representation
of
satisfying
- For any , is square-integrable;
- There exists an unramified character such that .
- .
In the remaining of this course, we will deduce this theorem from Arthur's simple trace formula.
11/26/2013
Application of the trace formula for compact quotients
To make life a bit easier, we are going to prove this theorem in the case where , and has trivial center to avoid minor technicality. We will first focus on the case where is compact and treat the general case next time.
Since is compact, is anisotropic and we can use the trace formula for the compact quotient (Theorem 29).
We will choose of the form where , , . We pick
- the characteristic function of ;
- the matrix coefficient of (it is compactly supported as is supercuspidal and has trivial center).
- This is the most interesting one: is allowed to vary depending on a parameter . Fix a maximal torus, , set of roots of . a root basis. the set of -positive roots. We parametrize the irreducible representations of with the -dominant weights (Theorem 21). Write the corresponding highest weight representation for . We take .
We need to know about these functions in order to proceed. The key input is the Weyl character formula, which we now review.
Let
be a basis of the free
-module
We say a function
is
polynomial if it is given by a polynomial in (the dual basis of)
. We say a function
is
rational if it is given by a rational function of
.
(Weyl character formula)
- Fix and suppose is regular semisimple (i.e., for any ). Then Here is the half sum of the positive roots and is the sign character. The denominator does not vanish by the assumption that is regular semisimple.
- Fix . Then is a polynomial function.
. Let
be the diagonal torus. Then
, given by
,
. The dominant weights are the non-negative integers. Then
This makes sense when
(i.e,
is regular semisimple) and recovers exactly the Weyl character formula for
. Moreover,
is the
-th symmetric power of the standard representation and
is a polynomial function.
Let
be a sequence of
-dominant weights satisfying: for any
,
as
(we say
far from the walls). Then for all
,
, we have
After conjugation, we may assume that
. Then
Since
far from the walls, the coefficients of the monomials of
go to infinity. Because
,
, thus
. Since
is uniformly bounded as
varies, the result follows.
¡õ
We now return to the trace formula. Fix a sequence of -dominant weights such that far from the walls. We choose by
We observe that
- If is an automorphic representation of such that for some , then has the desired property: is simply the equivariant projection , in particular, if and only if . Since is chosen to be a matrix coefficients, if and only if . So to prove the theorem, it is enough to show where is the regular representation of .
- The global orbital integral splits up as a product of local orbital integrals, provided all the measures are chosen carefully; the constants are not important for the proof.
Now we apply the trace formula and obtain Notice is a compact subset of , which does not depend on . So by Remark 106, the sum over can be replaced by a sum on a finite subset . Notice . We can always arrange that by choosing suitable matrix coefficient. Then Dividing by , we obtain that The first term is nonzero and is independent of . So if we can show that tends to zero, then for all sufficiently large .
Let us choose a measure on so that for any , This is allowable since is compact. So as is conjugation invariant. We conclude the orbital side is nonzero since by Corollary ##Cor:AFfarfromwalls , which finishes the proof of Theorem 44 in the compact case.
12/03/2013
Application of Arthur's simple trace formula
References for this section:
- Chenevier-Clozel, JAMS
- Clozel-Delorme, le theoreme de Paley-Wiener invariant pour les groupes reductifs, I, II
Today we we will remove the compact condition imposed on last time. We are going to use Arthur's simple trace formula (Theorem 31). As last time, we choose the test functions of the form and will ensure that for suitable choices of and , vanishes if is not -elliptic. We may assume that and .
Fix an -elliptic maximal torus. The existence of is equivalent to the existence of a compact inner form of (Theorem 25). The idea is to transfer functions (resp. conjugacy classes) on to functions (resp. conjugacy classes) on .
We fix such an and an isomorphism such that is an inner automorphism. Define . The fact (one needs to know a bit more about real groups) is that one can choose such that is defined over and the restriction is also defined over . Choose such an and let to be the real torus which becomes after extension of scalars. So we have an isomorphism over .
Suppose
,
. Then the diagonal torus
is an
-elliptic torus. Choose
also to be diagonal torus. Then one can find an isomorphism
which restricts to an isomorphism
defined over
.
Recall (Theorem 26) that the square-integrable representations of fall into packets indexed by -orbits of regular elements . Each packet contains exactly representations with the infinitesimal character . Similarly, the irreducible representations of the compact group are in bijection with -orbits of regular elements . This differs from the highest weight parametrization by a -shift (Example 33).
So another way to phrase the parametrization of discrete series of is to put them in packets , where varies over irreducible representations of . The assignment does not depend on the choice of the isomorphism . This is a special case of the (local) Langlands functoriality (the -groups of and are the same and is "more quasi-split" than ). Dual to this transfer we should have a transfer of conjugacy classes. Let be an -elliptic element. Then is -conjugate to an element of the fixed torus . Without loss of generality, we may assume . We define , well-defined up to -conjugacy.
We can further choose all the 's to have support in a fixed compact subset of . Now applying Arthur's trace formula gives Let vary so that all have support in a fixed compact subset . Then the orbital side becomes where is a finite set of -elliptic elements of . But by the previous theorem, we obtain Let far from walls as last time, we obtain that as an application of Weyl character formula. In particular, if is sufficiently far from the wall, then there exists a cuspidal automorphic representation such that . Thus we have constructed the automorphic representation with all desired local properties in Theorem 44.